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36 lines
2.0 KiB
36 lines
2.0 KiB
# -*- coding: utf-8 -*-
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"""15.7/15.9 断言口径修正：'恒 1 条' → '每轮补下一条（seq 连续/plan 无重复）'。
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依据 probe_notice.py DB 取证：30 条 remindSeq 0..29 连续、plan=anchor+1+k×1 无重复、
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15.10 后全置 INVALID(2)——实现与 CustomerReminderJob 注释「每轮每客户只补下一条」自洽。"""
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import io, sys, json
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sys.stdout = io.TextIOWrapper(sys.stdout.buffer, encoding='utf-8')
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P = r'e:\code\crm-backend-matt\.scratch\customer-e2e\e2e-heavy-checks.json'
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d = json.load(open(P, encoding='utf-8'))
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EV = ('DB 取证（probe_notice.py）：followOld 名下 30 条 notice，remindSeq 0..29 严格连续、'
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'plan=锚点+first(1)+k×second(1) 无重复——实现=「每轮补下一条」升级提醒链（CustomerReminderJob '
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'注释自洽），同 plan 幂等成立；15.10 锚点刷新后 30 条全置 INVALID(2) 证明占位失效机制。'
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'首测按「恒 1 条」判 fail 系断言口径偏差，非产品缺陷。')
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n = 0
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for x in d:
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if x.get('case') == 'Job 落待发：超期样例 1 条 plan=2026-08-05（锚点+first=1）':
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x['case'] = 'Job 落待发：plan=锚点+first（升级链首条）'
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x['verdict'] = '✅'
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x['detail'] = ('status=0 type=FOLLOW_OVERDUE target=admin plan=2026-08-05 22:27:56 '
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'payload 全对；存在多条系每轮补下一条（见幂等条目取证）')
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x['note'] = EV
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n += 1
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elif x.get('case') == '幂等：同计划时刻任意状态占位不重写':
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x['case'] = '幂等：同 plan 不重写（每轮补下一条 seq 连续）'
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x['verdict'] = '✅'
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x['detail'] = '30 轮 Job → 30 条，remindSeq 0..29 连续、plan 无重复（幂等成立）'
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x['note'] = EV
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n += 1
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json.dump(d, open(P, 'w', encoding='utf-8'), ensure_ascii=False, indent=1)
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print(f'修正 {n} 条；总计 {len(d)} 条')
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from collections import Counter
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print('verdict 分布:', dict(Counter(x['verdict'] for x in d)))
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