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44 lines
2.2 KiB
44 lines
2.2 KiB
# -*- coding: utf-8 -*-
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"""D-07 修复前置：sys_dept.ancestors 数据完整性校验（前缀查询口径 vs 递归口径一致才可上）。
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py -X utf8 .scratch/customer-defectfix/check-ancestors.py
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"""
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import pymysql
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def dbq(sql, args=None):
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with pymysql.connect(host='8.129.84.155', port=3306, user='root', password='Itc@123456',
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database='crm', charset='utf8mb4', autocommit=True,
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connect_timeout=10, cursorclass=pymysql.cursors.DictCursor) as conn, \
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conn.cursor() as cur:
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cur.execute(sql, args)
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return cur.fetchall()
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rows = dbq("SELECT COUNT(*) total, "
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"SUM(CASE WHEN ancestors IS NULL OR ancestors='' THEN 1 ELSE 0 END) blank "
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"FROM sys_dept")
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print(f"sys_dept 总数={rows[0]['total']} ancestors空={rows[0]['blank']}")
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# 以「广东保伦」根部门（罗伟健所在）为样本：递归子树 vs 前缀查询 必须同数
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root = dbq("SELECT dept_id FROM crm_auth_user WHERE id=739564171091247104")[0]['dept_id']
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drow = dbq("SELECT id, dept_name, ancestors, parent_id FROM sys_dept WHERE id=%s", (root,))[0]
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print(f"样本根部门 id={drow['id']} name={drow['dept_name']} ancestors={drow['ancestors']} "
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f"parent_id={drow['parent_id']}")
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chain = f"{drow['ancestors']},{drow['id']}"
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rec = dbq("WITH RECURSIVE t AS (SELECT id FROM sys_dept WHERE id=%s "
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"UNION ALL SELECT d.id FROM sys_dept d JOIN t ON d.parent_id=t.id) "
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"SELECT COUNT(*) c FROM t", (root,))[0]['c']
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pfx = dbq("SELECT COUNT(*) c FROM sys_dept WHERE ancestors=%s OR ancestors LIKE %s",
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(chain, chain + ',%'))[0]['c'] + 1 # +1 = 自身
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print(f"递归口径子树={rec} 前缀口径(含自身)={pfx} {'✅ 一致' if rec == pfx else '❌ 不一致——禁止用前缀查询'}")
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# 逐部门抽查：每个部门的 ancestors 末段必须等于其 parent_id（链未断）
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bad = dbq("SELECT COUNT(*) c FROM sys_dept WHERE parent_id<>0 AND "
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"ancestors NOT LIKE CONCAT('%', parent_id)")
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print(f"ancestors 末段≠parent_id 的断链行={bad[0]['c']}")
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# 顶层行（parent_id=0）ancestors 必须为 '0'
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badroot = dbq("SELECT COUNT(*) c FROM sys_dept WHERE parent_id=0 AND ancestors<>'0'")
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print(f"顶层 ancestors≠'0' 的行={badroot[0]['c']}")
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